Theorems No Circle Class 10 Ch-10
PROOF OF IMPORTANT THEOREMS ON THE CIRCLE
Coplete explanation with proof of Theorem 10.1 and theorem 10.2 class 10 chapter 10, strictly based on NCERT Book and syllabus.
Statement :
Tangent is always perpendicular to the radius at the point of contact.
Given: In circle C(o,r), XY is tangent to the circle at point P.
To Prove: OP ⊥ XY
Construction :
Take any arbitrary point Q (other than P ) on the line XY and join OQ which meet the circle at point R.
Proof:
In order to prove that OP ⊥ XY it is sufficient to prove that OP is the smallest line segment than all the line segments obtained by joining O with any point on XY.
OP = OR .......... (Equal radii)
Now OQ = OR + RQ
OQ = OP + RQ
Subtract RQ from the R.H.D. we get
OQ > OP or
OP < OQ
But Q is an arbitrary point on XY
⇒ OP is the smallest line segment and smallest line segment is always perpendicular.
Hence OP ⊥ XY
Hence prove the required theorem
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THEOREM 10.2 CHAPTER 10 CLASS 10
Statement
Prove that length of tangents from external point to the circle are equal in length.
Given : AC and BC are two tangents from external point to the circle.
To Prove : AC = BC
Construction: Join OA, OB and OC
Proof:
Since radius is always perpendicular to the tangent.
∴ ã„¥1 = ã„¥2 = 90o
In ΔAOC and ΔBOC
OA = OB ............... (Equal radii)
OC = OC .............. (common side)
ã„¥1 = ã„¥2 .............. (Each = 90o
∴ By RHS ≌ rule
ΔAOC ≌ ΔBOC
⇒ AC = BC .............By CPCT
Hence prove the required result
Results of other important theorems on circle
Theorem : If AB and CD are two chords of the circle intersect each other at point p inside or outside the circle then:-
PA X PB = PC X PD
This result rmain same in both the cases inside and out side the circle.
When Chord intersect each other Inside the circle
When chords intersect each other Outside the circle
Theorem : If chord AB of a circle intersect the tangent of the same circle at point P outside the circle then
PA X PB = PT2
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