MATHEMATICS ASSIGNMENT CLASS 10    CHAPTER-11 Area related to Plane Figures Math Assignment Class X : Chapter 11 : Area Related to Plane Figures like triangle, quadrilaterals and circle etc. 

Theorem 6.6 class 10 mathematics, theorem based on the ratio of area of two similar triangles, theorem based on the relationship between ratio of areas and the corresponding sides. Statement :  The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Given :-   \[\Delta ABC\sim \Delta PQR\] To Prove :- \[\frac{Ar(\Delta ABC)}{Ar(\Delta PQR)}=\left ( \frac{AB}{PQ} \right )^{2}=\left ( \frac{BC}{QR} \right )^{2}=\left ( \frac{AC}{PR} \right )^{2}\] Construction :-      \[Draw\: \: AM\perp BC\: \: and\: PN\perp QR\] Proof :-      \[\Delta ABC\sim \Delta PQR\] \[\therefore \: \: \frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}......(1)\]   \[and\: \: \angle A=\angle P,\: \angle B=\angle Q\: ,\: \angle C=\angle R\] \[Area\: of\: \Delta ABC=\frac{1}{2}\times BC\times AM\] \[Area\: of\: \Delta PQR=\frac{1}{2}\times QR\times PN\] \[\frac{Ar(\Delta ABC)}{Ar(\Delta P...

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