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CBSE Assignments class 09 Mathematics

  Mathematics Assignments & Worksheets  For  Class IX Chapter-wise mathematics assignment for class 09. Important and useful extra questions strictly according to the CBSE syllabus and pattern with answer key CBSE Mathematics is a very good platform for the students and is contain the assignments for the students from 9 th  to 12 th  standard.  Here students can find very useful content which is very helpful to handle final examinations effectively.  For better understanding of the topic students should revise NCERT book with all examples and then start solving the chapter-wise assignments.  These assignments cover all the topics and are strictly according to the CBSE syllabus.  With the help of these assignments students can easily achieve the examination level and  can reach at the maximum height. Class 09 Mathematics    Assignment Case Study Based Questions Class IX 

Theorem Class 10 Ratio of Area of two similar triangles

Theorem 6.6 class 10 mathematics, theorem based on the ratio of area of two similar triangles, theorem based on the relationship between ratio of areas and the corresponding sides.

Statement : 
The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
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Given :-  \[\Delta ABC\sim \Delta PQR\]
To Prove :-\[\frac{Ar(\Delta ABC)}{Ar(\Delta PQR)}=\left ( \frac{AB}{PQ} \right )^{2}=\left ( \frac{BC}{QR} \right )^{2}=\left ( \frac{AC}{PR} \right )^{2}\]
Construction :-    \[Draw\: \: AM\perp BC\: \: and\: PN\perp QR\]
Proof :-    \[\Delta ABC\sim \Delta PQR\]
\[\therefore \: \: \frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}......(1)\] 
\[and\: \: \angle A=\angle P,\: \angle B=\angle Q\: ,\: \angle C=\angle R\]
\[Area\: of\: \Delta ABC=\frac{1}{2}\times BC\times AM\]
\[Area\: of\: \Delta PQR=\frac{1}{2}\times QR\times PN\]
\[\frac{Ar(\Delta ABC)}{Ar(\Delta PQR)}=\frac{\frac{1}{2}\times BC\times AM}{\frac{1}{2}\times QR\times PN}=\frac{BC}{QR}\times \frac{AM}{PN}\]
\[Now\: in \Delta ABM and \Delta PQN\]
\[\angle B=\angle Q\: \: \: \: ......\: (\because \Delta ABC\sim \Delta PQR)\]
\[\angle 1=\angle 2\: \: ......\: \: (\because each=90^{o})\]
\[\therefore \Delta ABM\sim \Delta PQN\]
\[\Rightarrow \: \: \: \frac{AM}{PN}=\frac{AB}{PQ}\]
\[But\: \frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}\]
\[\frac{AM}{PN}=\frac{BC}{QR}\]
\[\frac{Ar(\Delta ABC)}{Ar(\Delta PQR)}=\frac{BC}{QR}\times \frac{AM}{PN}=\frac{BC}{QR}\times \frac{BC}{QR}=\left ( \frac{BC}{QR} \right )^{2}...........(2)\]
From (1) and (2)
\[\frac{Ar(\Delta ABC)}{Ar(\Delta PQR)}=\left ( \frac{AB}{PQ} \right )^{2}=\left ( \frac{BC}{QR} \right )^{2}=\left ( \frac{AC}{PR} \right )^{2}\]
Hence prove the required theorem


Side-Side-Side Similarity Rule :-
If three sides of one triangle are proportional to the corresponding three sides of other triangle then triangles are similar to each other and the condition is called SSS similarity () rule.

Side-Angle-Side Similarity Rule:-
If two sides of one triangle are proportional to the corresponding two sides of other triangle and the angle between the sides are equal to each other then triangles are similar to each other and the condition is called SAS  similarity (∿) rule.

Angle-Angle-Angle Similarity Rule :-
If three angles of one triangle are equal to the three angles of other triangle, then triangles are similar to each other and the condition is called AAA similarity () rule.

Angle-Angle Similarity Rule :-
If two angles of one triangle are equal to the two angles of other triangle, then triangles are similar to each other and the condition is called AA (similarity rule.

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