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Math Assignment Class XII Ch -06 | Application of Derivatives
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Math Assignment Class XII Ch - 06
Application of Derivatives
MATHEMATICS ASSIGNMENT OF CHAPTER 06
RATE OF CHANGE OF QUANTITIES
Question 1
A particle moves along the curve x2 = 2y. At what point, ordinate increases at the same rate as abscissa increases?
Answer (1, 1/2)
Solution Hint:
Differentiating the given equation
w. r. t. t
Now putting dy/dt = dx/dt and
find the value of x.
Putting the value of x in the
given equation and find the value of y
Question 2
The side of an equilateral triangle is increasing at the
rate of 2 cm/s. At what rate is its area increasing when the side of triangle
is 20 cm?
Answer: 20√3 cm2/s
Question 3
Volume of sphere is increasing at the rate of 3cm3/s.
Find the rate of increase of surface area, when radius is 2 cm
Answer: 3cm2/s
Question 4
For the curve y = 5x – 2x3. If x increases at the
rate of 2 unit/sec., find the rate of change of the slope of the curve when x =
3.
Answer: -72 unit /sec
Question 5
A man 2m high walks at a uniform speed of 6km/h away from
the lamp post 6m high. Find the rate at which the length of his shadow increases.
Answer : 3km/h
Solution Hint
AB = 6m, CD = 2m dy / dt = 6 km/h,
Let AC = y, CE = x, AE = x + y,
To find : dx/dt = ?
△ABE ~ △ CDE
∴
⇒ y = 2x
Differentiating on both side w.r.t. t we get
INCREASING & DECREASING OF FUNCTIONS
Without using derivative show that the function f(x) = 4x3 – 18x2
+ 27x – 7 is always increasing in R
Strictly Decreasing in (-2, 6)
Question 3
Find the intervals in which the function f(x) = x4 / 4 – x3 – 5x2 + 24x + 12 is
i) Strictly increasing ii) Strictly decreasing
Answer:
Strictly Decreasing in (-∞, 3)⋃(2, 4)
Question 4
Find the interval in which the function:
f(x) = sin4x + cos4x, 0 ≤ x < Ï€/2
is strictly increasing or strictly decreasing.
Answer:
Strictly increasing in (π/4, π/2)
Strictly decreasing in (0, π/4)
Question 5
Find the intervals in which f(x) = sin3x - cos3x, 0<x<Ï€, is strictly increasing or strictly decreasing.
Answer:
Strictly increasing in (0, Ï€/4) ⋃ (7Ï€/12, 11Ï€/12)
Strictly decreasing in (Ï€/4, 7Ï€/12) ⋃ (11Ï€/12, Ï€)
Question 6
Strictly increasing in (-∞, -2)⋃
Strictly Decreasing in (-2, 3)
Question 8
Find the interval in which the following functions are strictly increasing and strictly decreasing : f(x) = 2x3 – 12x2 + 18x + 5
Answer:
Strictly increasing in (-∞, 1)⋃
Strictly Decreasing in (1, 3)
Strictly increasing in
Strictly Decreasing in
Question 10
Find the intervals in which the function given by f(x) = sin3x, x∈ [0, Ï€/2] is increasing and decreasing.
Answer
Increasing on [0, π/6]
Question 11 Let f(x) be a continuous function on [a, b] and differentiable on (a, b). Then, this function f(x) is strictly increasing in (a, b) if
Question 12 The function f(x) = x3 – 3x2 + 12x – 18 is :(D) strictly decreasing on (– ∞ , 0)
Answer bQuestion 13 Show that f(x) = ex – e–x + x – tan–1 x is strictly increasing in its domain.
Solution
∴ f is strictly increasing over its domail RQuestion 14: Find the intervals in which the function
Question 15:
(A) f’(x) < 0, ∀ x ∈ (a, b)
(B) f’(x) > 0, ∀ x ∈ (a, b)
(C) f’(x) = 0, ∀ x ∈ (a, b)
(D) f(x) > 0, ∀ x ∈ (a, b)
Ans: b
(A) strictly decreasing on R
(B) strictly increasing on R
(C) neither strictly increasing nor strictly decreasing on R
Solution:
For strictly increasing / decreasing, put f’(x) = 0 ⇒ x = e, x > 0
For strictly increasing, x ∈ (0, e ) and for strictly decreasing x
Find the absolute maximum and absolute minimum values of the function f given by , on the interval [1, 2].
Answer: Absolute maximum value = 5/2
Absolute minimum value = 2
MAXIMA AND MINIMA
Question 1
If , then find the maximum value of f(x)
Ans: 3/4
Solution Hint:
f(x) is maximum if 4x2 + 2x + 1 is minimum
g(x) = 4x2 + 2x + 1
g'(x) = 8x + 2
For critical point g'(x) =0 ⇒ x = -1/4
g''(x) = 8 > 0
⇒ g(x) is minimum at x = -1/4
Minimum value of g(x) = 3/4
⇒ f(x) is maximum at x = 3/4
Question 2
Find the maximum value of
Ans: 1/e
Solution Hint
Find the derivative of f(x) we get
f ' (x) = 0 ⇒ x = 0 and e (critical points)
But at x = 0 logx is not defined so we have x = e only
Now find f '' (x) we get
Question 7 Show that the function f(x) = 4x3 – 18x2 + 27x – 7 has neither maxima nor minima.
Solution: f ′ (x) = 12x2 − 36x + 27
= 3 (2 x -3)2 ≥ 0 for all x ∈ R
∴ f is increasing on R .
Hence f(x) does not have maxima or minima.
As at x = 1, 'f' attains local maximum value, f’(1) = 0 ⇒ a = 120
Now, f’(x) = 4x3 – 124x + 120
= 4(x - 1)(x2 + x - 30)
= 4(x - 1)(x - 5)(x + 6)
Critical Points are x = - 6, 1, 5
f’’(x) = 12x2 – 124
f’’(-6) > 0, f’’(5) > 0 and f’’(1) < 0
So f attains local maximum value at x = 1 and local minimum value at x = - 6, 5
Question 9:
The perimeter of a rectangular metallic sheet is 300 cm. It is rolled along one of its sides to form a cylinder. Find the dimensions of the rectangular sheet so that volume of cylinder so formed is maximum.
Solution: Let length of rectangle be x cm and breadth be (150 – x) cm.
Let r be the radius of cyllander
Circumference of base of cyllander = 2Ï€r = x
Volume of cyllinder = πr2h =
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