Math Assignment Class XII Ch-04

Math Assignment Class XII Ch - 04
DETERMINANTS

Extra questions of chapter 04 Determinants class XII with answers and hints to the difficult questions, strictly according to the CBSE syllabus. Important and useful math. assignment for the students of class XII

MATHEMATICS ASSIGNMENT ON

DETERMINANTS (XII)

Strictly according to the CBSE Board

Question 1

Find the value of k for which matrix A is a singular matrix

${A=\left [ \begin{matrix}k & 8 \\4 & 2k \\\end{matrix} \right ]}$

Ans: 土 4

Question 2

If A is a square matrix of order 3 and |A| = -4, then find the value of |adj A|

Ans: 16

Question 3

$If\: A=\left [ \begin{matrix}\alpha & 2 \\2 & \alpha \\\end{matrix} \right ]$ ,

and |A³| = 27, then find the value of α

Ans: 土√7

Question 4

$If\: \: \left|\begin{matrix}5 & 3 & -1 \\-7 & x & -3 \\9 & 6 & -2 \\\end{matrix} \right|=0$ , then find the value of x

Ans : x = 9

Question 5

$If\: A=\left [ \begin{matrix}2 & -3 \\5 & -4 \\\end{matrix} \right ],$ $\: B=\left [ \begin{matrix}1 & -2 \\3 & 5 \\\end{matrix} \right ]$

then verify that |AB| = |A||B|

Solution Hint: |AB| = 77 and |A||B| = 7 x 11 = 77

Question 6

$Evaluate\: \left [ \begin{matrix}a+ib & c+id \\-c+id & a-ib \\\end{matrix} \right ]$

Ans: a² + b² + c² + d²

Question 7

$Evaluate\: \left [ \begin{matrix}cos15^{o} & sin15^{o} \\sin75^{o} & cos75^{o} \\\end{matrix} \right ]$

Ans: 0

Question 8

For what value of x, the matrix A is singular

$A= \left [ \begin{matrix}5-x & x+1 \\2 & 4 \\\end{matrix} \right ]$

Question 9

Find the area of triangle with vertices A(5, 4), B(-2, 4), C(2, -6)

Ans: 35 sq unit

Question 10

Using determinants show that the points (2, 3), (-1, -2) and (5, 8) are collinear

Solution Hint:

Find area of triangle by taking above given points as vertices.

If area of triangle = 0 then points are collinear.

Question 11

Using determinants find the value of k so that the points (k, 2 - 2k), (- k + 1, 2k), and (- 4 - k, 6 - 2k) may be collinear

Ans: k = -1, 1/2

Question 12
Using determinants, find the equation of line joining the points (3,1), and (9,3)

Ans: x - 3y = 0

Question 13

Find the value of k, if area of triangle is 4 square units whose vertices are (-2,0), (0,4), and (0, k)

Ans: K = 0, 8

Question 14

Find the value of |AB| if matrices A and B are given below

$A=\left [ \begin{matrix}1 & 2 \\3 & -1 \\\end{matrix} \right ]$ and $B=\left [ \begin{matrix}1 & 0 \\-1 & 0 \\\end{matrix} \right ]$

Ans: 0

Question 15

Find the value of x if matrix A is a singular matrix
$A=\left [ \begin{matrix}5x & 2 \\-10 & 1 \\\end{matrix} \right ]$

Ans: x = -4

Question 16

Find the product : $\left [ \begin{matrix}1 & -1 & 0 \\2 & 3 & 4 \\0 & 1 & 2 \\\end{matrix} \right ]\left [ \begin{matrix}2 & 2 & -4 \\-4 & 2 & -4 \\2 & -1 & 5 \\\end{matrix} \right ]$

Hence solve the following system of equations
x - y = 3, 2x + 3y + 4z = 17, y + 2z = 7

Ans: x = 2, y = -1, z = 4

Solution Hint
Let given matrices are A and C

$AC=\left [ \begin{matrix}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1 \\\end{matrix} \right ]=6I$

Now find the product AC we get

$A\times \frac{1}{6}C=I\: \: \Rightarrow \: \: A^{-1}=\frac{1}{6}C$
Now given system of equations can be written as

$A=\left [ \begin{matrix}1 & -1 & 0 \\2 & 3 & 4 \\0 & 1 & 2 \\\end{matrix} \right ], X=\left [ \begin{matrix}x \\y \\z\end{matrix} \right ], B=\left [ \begin{matrix} 3\\17 \\7\end{matrix} \right ]$

AX = B ⇒ X = A^-1B

$\Rightarrow X=\frac{1}{6}CB$

⇒ x = 2, y = -1, z = 4 is the required solution

Question 17

$If \: \: A =\left [ \begin{matrix}3 & -4 & 2 \\2 & 3 & 5 \\1 & 0 & 1 \\\end{matrix} \right ],$
Find A^-1and hence solve following system of equations

3x - 4y + 2z = -1, 2x + 3y + 5z = 7, x + z = 2

Ans: x = 3, y = 2, z = -1

Solution Hint:

Find |A| we find |A| = -9 ⇒ A is invertible

Find cofactors of A and then find Adj. A we get
$Adj. A =\left [ \begin{matrix}3 & 4 & -26 \\3 & 1 & -11 \\-3 & -4 & 17 \\\end{matrix} \right ],$
Find A^-1we get

$A^{-1} =\frac{1}{9}\left [ \begin{matrix}-3 & -4 & 26 \\-3 & -1 & 11 \\3 & 4 & -17 \\\end{matrix} \right ],$

Given system of equations can be written as AX = B
⇒ X= A^-1B

$\left [ \begin{matrix}x \\y \\z\end{matrix} \right ] =\frac{1}{9}\left [ \begin{matrix}-3 & -4 & 26 \\-3 & -1 & 11 \\3 & 4 & -17 \\\end{matrix} \right ]\left [ \begin{matrix} -1\\7 \\2\end{matrix} \right ]=\left [ \begin{matrix} 3\\2 \\-1\end{matrix} \right ]$

⇒ x = 3, y = 2, z = -1
Question 18

$\mathbf{\; If\; \; A=\left [ \begin{matrix}2 & -3 & 5 \\3 & 2 & -4 \\1 & 1 & -2 \\\end{matrix} \right ]}$

Find A^-1. Use A-1 to solve the system of equations.

2x – 3y + 5z = 11, 3x + 2y – 4z = - 5, x + y - 2z = - 3

Ans: x = 1, y = 2, z = 3

Solution Hint

Find the |A| we get |A| = -1

Find adjoint of A

$Agjoint \: A=\left| \begin{matrix}0 & -1 & 2 \\2 & -9 & 23 \\1 & -5 & 13 \\\end{matrix}\right|$

Solve: X = A^-1B we get x = 1, y = 2, z = 3

Question 19

Show that the matrix A satisfies the equation A² - 4A - 5I = O and hence find A^-1
$A=\left [ \begin{matrix}1 & 2 & 2 \\2 & 1 & 2 \\2 & 2 & 1 \\\end{matrix} \right ]$

Ans:

$A=\frac{1}{5}\left [ \begin{matrix}-3 & 2 & 2 \\2 & -3 & 2 \\2 & 2 & -3 \\\end{matrix} \right ]$

Question 20

Find the matrix X for which

$\left [ \begin{matrix}1 & -4 \\3 & -2 \\\end{matrix} \right ]X=\left [ \begin{matrix}-16 & -6 \\ 7&2 \\\end{matrix} \right ]$

Ans

$X=\left [ \begin{matrix}6 & 2 \\11/2 & 2 \\\end{matrix} \right ]$

Question 21

$If\: \: A^{-1}=\left [ \begin{matrix}3 & -1 & 1 \\-15 & 6 & -5 \\5 & -2 & 2 \\\end{matrix} \right ]$ $and\: \: B=\left [ \begin{matrix}1 & 2 & -2 \\-1 & 3 & 0 \\0 & -2 & 2 \\\end{matrix} \right ]$

Find (AB)^-1

Ans:

$Ans \: \: \: (AB)^{-1}=\left [ \begin{matrix}9 & -3 & 5 \\-2 & 1 & 0 \\1 & 0 & 2 \\\end{matrix} \right ]$

Question 22

Solve the following system of equations

x + y + z = 3, 2x - y + z = -1, 2x + y - 3z = -9

Ans: x = -8/7, y=10/7, z=19/7

Question 23

Solve the following system of equations

$\frac{2}{x}+\frac{3}{y}+\frac{10}{z}=4,$

$\frac{4}{x}-\frac{6}{y}+\frac{5}{z}=1,$

$\frac{6}{x}+\frac{9}{y}-\frac{20}{z}=2$ where x, y, z ≠ 0

Ans: x = 2, y = 3, z = 5

Question 24

If A = $\begin{bmatrix}1 & 2 \\3 & -5 \\\end{bmatrix}$ , B = $\begin{bmatrix}1 & 0 \\0 & 2 \\\end{bmatrix}$ and X be a matrix such that A = BX, then find X

Answer: $\frac{1}{2}\begin{bmatrix}2 & 4 \\3 & -5 \\\end{bmatrix}$

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