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### Math Assignment Class X Ch-3 | Linear Equations in Two Variables

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__CHAPTER 3
CLASS X__

__PAIR OF LINEAR EQUATIONS IN TWO VARIABLE__

**Extra questions of chapter 3 class 10 : Pair of Linear Equations in Two Variable with answer and hints . Useful math assignment for the students of class 10**

**For better results**

**Students should learn all the basic points of Chapter 3 Pair of Linear Equations in two variable.****Student should revise N C E R T book thoroughly with examples.****Now revise this assignment. This assignment integrate the knowledge of the students.**

**LEVEL-1**

**Q1 By comparing the ratios of the coefficients find the nature of sol./ graph / consistency or inconsistency**

**a) 2x - 3y = 1 ; x + 2y = 2**

**Ans: Unique solution, intersecting lines, consistent**

**b) 3x - y = 6 ; 6x - 2y = 4**

**Ans: No solution, parallel lines, inconsistent**

**c) x + 3y = 8 ; 2x - 3y = 12**

**Ans: Unique solution, intersecting lines, consistent**

**d) 9x + 3y + 12 = 0 ; 18x + 6y = - 24**

**Ans: Many solution, coincident lines, consistent**

**e) 6x - 3y +10 = 0 ; 2x – y + 9 = 0**

**Ans: No solution, parallel lines, inconsistent**

**Q2) Find the value of p so that the following equations have coincident lines**

**a) 2x + y - 5 = 0; 6x + 3y + p = 0 ****Ans [p = -15]**

**b) x + 2y + 7 = 0; 2x + py + 14 = 0 ****Ans [p = 4]**

**c) 3x + 4y + 2 = 0; 9x + 12y + p = 0 ** **Ans[p = 6]**

**d) x + 5y - 7 = 0 ; 4x + 20y + p = 0 ****Ans [p = -28]**

**Q3) Find k if the following equations are inconsistent**

**a) 8x + 5y = 9; kx + 10y = 15 ****Ans [k = 6 ]**

**b) (3k + 1)x + 3y - 2 = 0; (k ^{2 }+ 1)x + (k - 2)y - 5 = 0 **

**Ans[k = -1]**

**c) 3x + y = 1; (2k - 1)x + (k - 1)y = 2k + 1 ****Ans [k = 2]**

**d) kx + 3y = k – 3; 12x + ky = k ****Ans [k = -6]**

**Q4) Find a & b or k so that the following equations have infinitely many solutions**

**a) (a + b)x - 2by = 5a + 2b + 1; 3x - y = 14 ****Ans [a = 5, b = 1]**

**b) 2x - 3y = 7; (a + b)x - (a + b - 3)y = 4a + b ****Ans[-5, -1]**

**c) 2x + 3y = 7; (a - b)x - (a + b - 3)y = 3a + b - 2 ****Ans[a = 5, b = 1]**

**d) (2a - 1)x + 3y – 5 = 0; 3x + (b - 1)y – 2 = 0 ****Ans[a = 17/4, b= 11/5]**

**e) kx + 3y = 2k + 1; 2(k + 1)x + 9y = 7k + 1 ****Ans [k = 2]**

**f) 2x + 3y = 7; (k – 1)x + (k + 2)y = 3k ****Ans [k = 7]**

**Q5) Solve the following equations graphically**

**a) x + y = 3; 2x + 5y = 12 ****Ans [1, 2]**

**b) 2x + 3y + 5 = 0; 3x - 2y - 12 = 0 ****Ans [2,-3]**

**Q6 Solve the following equations graphically. Shade the area between lines and x-axis. Also find the area of the shaded triangle.**

**a) x + y = 5; 2x - y = - 2 ****[Sol. (1, 4) & Area= 12]**

**b) x - y + 1 = 0; 3x + 2y - 12 = 0 ****[Area= 7.5]**

**c) 2x + y = 6; 2x - y + 2 = 0 ****[Area= 8]**

**Q7) Solve 2(x - 1) = y & x + 3y = 15 graphically and find the coordinates where lines meet the y-axis. Also shade the triangle between the lines and y-axis. ****Ans [(3, 4), (0, -2), (0, 5)]**

**Q8) Solve x – y = 1 & 2x + y = 8 graphically and shade the area between the lines and the y-axis. Also find the area of the triangle. ****Ans [Area = 13.5]**

**LEVEL-2**

**Q 9) Solve the following pair of linear equations in two variables**

**a) x+ y = 7 ; 3x - 2y = 1 ****Ans [3, 4]**

**b) 3x + 2y = 10 ; 4x - y = 6 ****Ans [2, 2]**

**c) ****y} ****Ans [2,-3]**

**d) 2x + y – 35 = 0 ; 3x + 4y - 65 = 0 ****Ans [15, 5]**

**e) ax + by = c ; ****bx + ay = 1 + c**** **

**f) ax + by = a - b ; ****bx - ay = a + b**** ****Ans [1, - 1]**

**g) ax + by = c ; bx - ay = 0 **** **

**h) x/a - y/b = 0 ; bx + ay = 4ab ****Ans[2a, 2b]**

**i) 6(ax + by) = 3a + 2b ; 6(bx + ay) = 3b + 2a ****Ans [1/2, 1/3]**

**j) - 6x + 5y = 2 ; - 5x + 6y = 9 ****Ans[3, 4]**

**k) ax + by = a ^{2 }+ b^{2} ; bx - ay = 0 **

**Ans [a, b]**

**l) 23x - 29y = 98 ; 29x - 23y = 110 ****Ans [3, - 1]**

**m) 99x + 101y = 499 ; 101x + 99y = 501 ****Ans [x = 3, y = 2]**

**n) a(x + y) + b(x - y) = a ^{2 }– ab + b^{2} ; **

**a(x + y) - b(x - y) = a**

^{2 }+ ab + b^{2 }**o) (a - b)x + (a + b)y = a ^{2 }- 2ab - b^{2 }; (a + b)(x + y) = a^{2 }+ b^{2 } **

** **

**p) 2(ax - by) + (a + 4b) = 0 ;**^{ }**2(bx + ay) + (b - 4a) = 0**** ****Ans [-1/2, 2]**

**q) x**** + y = 5xy ; 3x + 2y = 13xy ****Ans [x = 1/2 , y = 1/3]**

**r)**

**LEVEL-3**

**PROBLEMS BASED ON DAILY LIFE SITUATIONS**

**Q10) Find two numbers whose sum is 75 and difference is 15 **

**Ans [45 and 30]**

**Q11) Sum of two numbers is 8. Find the numbers if sum of their reciprocal is 8/15.**

**Q12) The ratio of incomes of two persons is 9 : 7 and the ratio of their expenditure is 4 : 3 If each of them saves Rs 200/ month, find their monthly incomes. **

**Ans [Rs1800 & Rs 1400]**

**Q13) A person can row downstream 20km in 2 hours. And upstream 4km in 2 hours. Find the speed of boat in still water and that of the current. **

**Ans [6,4]**

**Q14) A boat covers 32 km upstream and 36 km downstream in 7 hours. Also it covers 40 km upstream and 48 km downstream in 9 hours. Find the speed of the boat in still water and that of the stream. **

**Ans [10 km/h and 2 km/h]**

**Q 15) If 2 is subtracted from the numerator and 1 is added to the denominator, a fraction becomes 1/2 , but when 4 is added to the numerator and 3 is subtracted from the denominator , it becomes 3/2. Find the fractions. **

**Ans [8/11]**

**Q 16 37 pens and 53 pencils together cost Rs 320, while 53 pens and 37 pencils together cost Rs 400. Find the cost of a pen and that of a pencil. **

**Ans [Rs 6.50 and Rs 1.50]**

**Q 17) In a two digit number , the ten’s digit is three times the unit’s digit. When the number is decreased by 54, the digits are reversed. Find the number. **

**Ans [93]**

**Q 18) The sum of the two digit number and the number obtained by reversing the order of its digits is 121, and the two digits are differ by 3. Find the numbers. **

**Ans [47 or 74]**

**Q 19) The sum of a two digit number and the number formed by interchanging the digits is 110. If 10 is subtracted from the first number , the new number is 4 more than 5 times the sum of the digits in the first number. Find the first number **

**Ans [64] **

**Q 20) A fraction is such that if the numerator is multiplied by 3 and the denominator is reduced by 3, we get 18/11, but if the numerator is increased by 8 and the denominator is doubled , we get 2/5. Find the fraction. **

**Ans [12/25]**

**Q 21) The denominator of a fraction is 4 more than twice the numerator. When both the numerator and denominator are decreased by 6, then the denominator becomes 12 times the numerator. Find the fraction **

**Ans [7/18]**

**Q 22) If twice the son’s age in years is added to the fathers age, the sum is 70. But if twice the father’s age is added to the son’s age, the sum is 95. Find the age of father and son. Ans [40, 15]**

**Q 23) Two years ago, a father was 5 times as old as his son. Two years later , his age will be 8 more than 3 times the age of his son. Find the present ages of father and son. **

**Ans [42, 10] **

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**HIGHER ORDER THINKING SKILL (HOTS)**

Question 24)

Question 25)

Question 26)

Ans: x = 8, y = 3

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Good collections

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