Lesson Plan Math Class X (Ch-7) | Coordinate Geometry

E- LESSON PLAN SUBJECT MATHEMATICS CLASS 10

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TEACHER'S NAME :

Dinesh Kumar

SCHOOL :

RMB DAV CENTENARY PUBLIC SCHOOL NAWANSHAHR

SUBJECT : MATHEMATICS

CLASS : X STANDARD

BOARD : CBSE

LESSON TOPIC / TITLE :

CHAPTER : 07

COORDINATE GEOMETRY

ESTIMATED DURATION:

This chapter is divided into EIGHT modules and it is completed in TWENTY class meetings.

PRE- REQUISITE KNOWLEDGE:-

Knowledge of coordinate geometry class 9^th .

Properties of different types of quadrilaterals chapter 8 class 9th .

TEACHING AIDS: Green Board, Chalk, Duster, Charts, smart board, laptop, projector etc.

METHODOLOGY: Demonstration and Lecture method.

LEARNING OBJECTIVES:

Concept and introduction of coordinate geometry.

Graphs of linear equations and method of representing the ordered pairs on the graph.

Distance formula and its applications in different problems.

Different types of quadrilateral by using distance formula.

Collinearity of three points by using distance formula.

Section formula (internal division of the line), mid- point formula and the related problems.

EXPECTED OUTCOMES:-

After studying this lesson students should

Learn the formulas of finding the distance between two points,

Able to find the collinearity of three points.

Able to find the types of quadrilateral by using distance formula.

Able to understand section formula and mid-point formula,

RESOURCES
NCERT Text book of Mathematics
NCERT Exemplar Text Book
RESOURCE CENTRE at cbsemathematics.com
DAV Resource Material for class 10
KEY WORDS : Similarity, congruency, Median, Orthocenter, Incentre, Altitude, Centroid, etc.

PROCEDURE :-

Start the session by checking their previous knowledge, by asking the questions related to the Cartesian coordinate system and the method of representing them on the graphs.

After this explain the topic to the students step by step as follows.

Complete Explanation
Click Here

Introduction of coordinate geometry

Coordinate geometry is the combination of Algebra and Geometry. Before start this topic teacher will explain the Cartesian coordinate system.

Here teacher will explain Horizontal line, Vertical line, ordinate, abscissa, point on x-axis, point on y-axis, origin, quadrant etc.

Distance between two points

Plot two points on the graph and then derive the distance formula by applying the Pythagoras theorem.

Distance between two points A(x₁,y₁) and B(x₂, y₂) is given by

$\mathbf{ d=|AB|=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}}$

Collinearity of three points by distance formula

Explain the concept of collinearity of three points by using the distance formula.

Three or more points are said to be collinear if all the points lie on the straight line.

In order to prove that three points are collinear we shall prove the following statement.

If A(x₁, y₁) , B(x₂, y₂) and C(x₃, y₃) are three points on the line then

|AB| + |BC| = |AC|

Conditions for different types of quadrilateral

With the help of distance formula we can find the types of quadrilateral by using the following concepts.

Parallelograms: Opposite sides are equal but diagonals are not equal.

Rectangle: Opposite sides are equal and diagonals are also equal.

Rhombus: All sides are equal but diagonals are not equal.

Square: All sides are equal and diagonals are also equal.

Kite : Two pairs of adjacent sides are equal and diagonals are not equal.

Teacher will explain the concept by taking some examples.

Now teacher will Explain the problems related to the following statements.

Any point on the x-axis is (a, 0).

Any point of the y-axis is (0, b)

Any point given equidistant from two given points.

Section Formula

Now teacher will Explain the derivation of section formula and its implementation in the different problems.

If A(x₁,y₁) and B(x₂, y₂) are two points on the straight line and if point P(x, y) divide the line between A and B in m₁ : m₂, then by section formula:

$\mathbf{P(x,y)=\left ( \frac{m_{1}x_{2}+m_{2}x_{1}}{m_{1}+m_{2}},\frac{m_{1}y_{2}+m_{2}y_{1}}{m_{1}+m_{2}} \right )}$

Teacher will also explain the implementation of this formula in different problems. Teacher may also provide some problems to the students.

Mid Point Formula

After this teacher will introduce the Mid-Point formula and give some problems to the students for practice.

If A(x₁,y₁) and B(x₂, y₂) are two points on the straight line and if point P(x, y) is the mid - point of AB, then by Mid-Point formula.

$\mathbf{P(x,y)=\left (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2} \right )}$

Centroid of Triangle

Now teacher will give the knowledge of centroid of the triangle and suggest the formula used to find it.

If A(x₁, y₁) , B(x₂, y₂) and C(x₃, y₃) are three vertices of a triangle then Centroid P(x,y) of triangle is given by

$\mathbf{P(x,y)=\left ( \frac{x_{1}+x_{2}+x_{3}}{3},\frac{y_{1}+y_{2}+y_{3}}{3} \right )}$

Teacher may also assign some problems to the students to apply this formula.

STUDENTS DELIVERABLES:-

Review questions and formulas given by the teacher.

Students should make the presentation on the formulas and basic concepts of this chapter.

Solve N.C.E.R.T. problems with examples.

Solve assignment Multiple Choice Questions (MCQ) given by the teacher.

EXTENDED LEARNING:-

Students can extend their learning through the RESOURCE CENTRE and can find more valuable and interesting concepts on mathematics at cbsemathematics.com

ASSESSMENT TECHNIQUES:-

Assignment sheet will be given as home work at the end of the topic. Separate sheets which will include questions of logical thinking and Higher order thinking skills will be given to the above average students.
Class Test , Oral Test , worksheet and Assignments can be made the part of assessment.
Re-test(s) will be conducted on the basis of the performance of the students in the test.
FEEDBACK:
All those students who performed well will be appreciated positively, and all those who can not perform up to the mark will again be given some important tips, guidance and positive motivation to go through the topic again and then re-evaluated again.
If possible then provision of remedial classes can be made for batter results.

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